32m^2-80m+50=0

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Solution for 32m^2-80m+50=0 equation: 



32m^2-80m+50=0

a = 32; b = -80; c = +50;
Δ = b2-4ac
Δ = -802-4·32·50
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$m=\frac{-b}{2a}=\frac{80}{64}=1+1/4$

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